Oxygen gas reacts with powdered aluminum according to the following reaction:?

4Al(s)+3O2(g) yields 2Al2O3(s)


What volume of gas (in L), measured at 770 mmHg and 35 degrees C, is required to completely react with 53.9g of Al?Oxygen gas reacts with powdered aluminum according to the following reaction:?
37.4L


because (53.9g Al/26.98g/mol Al) x (3 mol O2/ 4 mol Al)=1.50 mol O2


then ((1.50 mol) x (62.4 L*mmHg/mol*K) x (308 K))/ 770 mmHg= 37.44L


and that's how you get it I think