4Al(s) + 3O2(g) -%26gt; 2Al2O3(s)
What volume of O2 gas (in L), measured at 763 mmHg and 35 degrees celsius, is required to completely react with 54.2 g of Al?Oxygen gas reacts with powdered aluminum according to the following reaction:?
moles Al = 54.2 g/ 26.9815 g/mol= 2.00
moles O2 = 2.00 x 3/4=1.5
V = 1.5 x 0.08206 x 308 K/ 1.00 atm = 37.9 L
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